0.01y^2-0.14y=-0.24

Solution for 0.01y^2-0.14y=-0.24 equation:

0.01y^2-0.14y=-0.24

We move all terms to the left:

0.01y^2-0.14y-(-0.24)=0

We add all the numbers together, and all the variables

0.01y^2-0.14y+0.24=0

a = 0.01; b = -0.14; c = +0.24;
Δ = b2-4ac
Δ = -0.142-4·0.01·0.24
Δ = 0.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.14)-\sqrt{0.01}}{2*0.01}=\frac{0.14-\sqrt{0.01}}{0.02}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.14)+\sqrt{0.01}}{2*0.01}=\frac{0.14+\sqrt{0.01}}{0.02}
$